The CDBM CDBC is an 8-stage parallel input se- rial output shift register A parallel serial control input en- ables individual JAM inputs to each of 8 . Texas Instruments and its subsidiaries (TI) reserve the right to make changes to their products or to discontinue any product or service without notice, and advise . CD The an 8-stage parallel input serial output shift register A parallel serial control input enables individual JAM inputs to each of 8 stages Q outputs are.

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Under these conditions, the chip does not advance these 8 bits at all and SER IN is completely ignored. CD – Q8 output. Is this not happening? Basically I’m duplicating what a MCU does but at very slow speed. Input s n – HIGH I did this with one of the 8 inputs and in another test with two inputs simultaneously 3.


Clock falling doesn’t do a thing, as you would expect. I will never ask you to do anything that I wouldn’t do myself.


(PDF) CD4014 Datasheet download

According to the output table image CD – Q8 output. I’ve found some code online but unfortunately it is not helpful for understanding how the shift register works. CDBE with buttons and leds Q8. I did this before with a 74HC shift register and it clarified for me how it functions, but with the CD it’s a different story.

I thought that the AVR has Schmitt trigger inputs when a port is configured for digital input. CDBE with buttons and leds.

(PDF) CD Datasheet PDF Download – Line to 4-Line BCD Priority Encoder

I’m not sure if this is the correct datashet to do it but I got some results that I don’t understand. Here’s how I use the switches to duplicate what the MCU does: MarkT Brattain Member Posts: In either case, after the clock rises, Q6, Q7, and Q8 are available on their respective output pins.

What does Qn-1 do? Mechanical switches should never drive logic clocks directly for this reason! While doing the tests I wrote down the output state of Q8. Have you hit all pins with a logic datzsheet to make sure they have the voltage you think they do?


MarkT on Oct 06, I’ve just updated the schematic image. All bets are off until you debounce the push button driving the clock input – you will be getting anything from 1 to hundreds of edges everytime you press it at the moment. CD – truth table.

The first one was wrong, the 8 input switches should be connected to VDD, not ground. This is called a “preset” function. Q7 goes into Q8. What does Q1 Internal mean? Input s n – LOW 5.

JoeN on Oct 09, Data Sheet for the CD I read the truth table simply. PE – LOW 6. Here is fd4014 in English. It looks like a weird serial-in, last-three-bits-out, with parallel 8 bit preset shift register to me.

JoeN Edison Member Posts: CD BE – Understanding the truth table.

That is what the data sheet says, at least.